FramerDave
PFG, Picture Framing God
Ok, this one's bugging me, especially since I aced geometry in school, and I know the answer must be pretty straight forward.
Let's say you have an octagonal frame and it is to be 12 3/4 inches wide and tall. How do you determine the length of each side? I know the answer probably involves the square root of 2 since you end up with 45 degree right triangles. Beyond that I'm having a brain freeze.
I suppose I could brute force it and cut a piece of board 12 3/4 inches square and work from there. But that's not terribly elegant.
Any ideas?
UPDATE: My algebra teacher would be ashamed. I have gotten this far:
If S is the side, then then S times the square root of 2 plus 2S equals 12 3/4. Then it gets really messy.
Let's say you have an octagonal frame and it is to be 12 3/4 inches wide and tall. How do you determine the length of each side? I know the answer probably involves the square root of 2 since you end up with 45 degree right triangles. Beyond that I'm having a brain freeze.
I suppose I could brute force it and cut a piece of board 12 3/4 inches square and work from there. But that's not terribly elegant.
Any ideas?
UPDATE: My algebra teacher would be ashamed. I have gotten this far:
If S is the side, then then S times the square root of 2 plus 2S equals 12 3/4. Then it gets really messy.